X^2+0.0072x-0.036=0

Solution for X^2+0.0072x-0.036=0 equation:

X^2+0.0072X-0.036=0

a = 1; b = 0.0072; c = -0.036;
Δ = b2-4ac
Δ = 0.00722-4·1·(-0.036)
Δ = 0.14405184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0072)-\sqrt{0.14405184}}{2*1}=\frac{-0.0072-\sqrt{0.14405184}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0072)+\sqrt{0.14405184}}{2*1}=\frac{-0.0072+\sqrt{0.14405184}}{2}
$